Let the function f (x) be a quadratic function and the coefficient of the quadratic term be a. if the solution set of inequality f (x) greater than or equal to a + 1-x is [- 1,1], find the value range of F (x) on the interval [- 1,1]

Let the function f (x) be a quadratic function and the coefficient of the quadratic term be a. if the solution set of inequality f (x) greater than or equal to a + 1-x is [- 1,1], find the value range of F (x) on the interval [- 1,1]

Let f (x) = ax ² + bx + cf(x) ≥ a+1-xax ² + bx + c ≥ a+1-xax ² + (B + 1) x + c-a-1 ≥ 0, the solution set is [- 1,1], then ax ² + (b+1)x + c-a-1 ≥ 0,g(x) = ax ² + (B + 1) x + c-a-1 can be expressed as a (x + 1) (x - 1) and

Why is the multiplication of two quadratic equations equal to square B Example X - 8x + 15 gets 0 One is 3 and the other is a 3A = 15 why

ax ²+ bx+c=0
Then X1 = [- B + √ (b) ²- c ²)]/ (2a)
x2=[-b-√(b ²- c ²)]/ (2a)
So x1x2 = [- B + √ (b) ²- c ²)] [-b-√(b ²- c ²)]/ (4a ²)
Molecular square difference
So x1x2 = (b) ²- b ²+ 4ac)/(4a ²)
=4ac/(4a ²)
=c/a
Here a = 1, B = 15
So x1x2 = 15 / 1 = 15

The multiplication of two numbers equals the addition of two numbers For example, 2 + 2 = 2 * 2 There should be other answers. I did it a long time ago and now I forget it. pass_ Op0 and Miao wine, thank you first. I remember that the result of adding (or multiplying) these two numbers seems to be a positive integer and a single digit.

0*0=0+0
When a and B are not 0,
a*b=a+b
a=a/b+1
A = B / (B-1) B is not equal to 1, and a is not equal to 1
For example, when B = 2, a = 2
When B = 3, a = 3 / 2
When B = 4, a = 4 / 3
.

About ax ²＋ BX + C = 0 and quadratic function y = ax ²＋ All formulas and conclusions of BX + C (clean point) I mean, summary

Equation: ax ²＋ bx＋c＝0
1. When B ²- 4ac0, the equation has two unequal real roots;
3. When B ²- When 4ac = 0, the equation has two equal real roots
4. If B ²- 4ac ≥ 0, then x = [- B ±√ (b) ²- 4ac)]/2a.
5. If X1 and X2 are the two roots of the equation respectively, then: X1 + x2 = - B / A; X1*X2=c/a.
Quadratic function y = ax ²＋ bx＋c
1. When B ²- 4ac0, the image has two intersections with the X axis;
3. When B ²- When 4ac = 0, the image has only one intersection with the X axis
4. If B ²- 4ac ≥ 0, the abscissa of the intersection of the image and the X axis is [- B + √ (b) respectively ²- 4ac)]/2a,[-b-√(b ²- 4ac)]/2a.
5. When a > 0, the image opening is upward; Otherwise, the opening is downward
6. When a and B are the same, the axis of symmetry is on the left side of Y axis; a. B when the sign is different, the axis of symmetry is on the right side of the Y axis
7. When C > 0, the image intersects the positive half axis with the Y axis

y=ax ²+ When does the quadratic function in BX + c c c > 0 write other judgment formulas and their reasons

Look at the function image. When the image intersects the positive half axis with the Y axis, C > 0
What formula did you say? Judge C or Delta? △=b ²- 4ac. If you don't understand, ask again

Use the quadratic function y = ax ²+ BX + C vertex coordinate formula, find the following function y = - 2x ²+ 5x + 3 fast

a=-2,b=5,c=3
So - B / 2A = 5 / 4
(4ac-b ²)/ 4a=49/8
So the vertex is (5 / 4,49 / 8)