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PA^2+PC^2=PB^2+PD^2 不妨設P在AD上方,過P作PF垂直AD於E,垂直BC於F 由畢氏定理PA^2=PE^2+AE^2 PC^2=PF^2+CF^2 PB^2=PF^2+BF^2 PD^2=PE^2+DE^2 而AE=BF,ED=FC 則PA^2+PC^2=PB^2+PD^2
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