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由圖得:四邊形ABCD是平行四邊形,∴AB‖=CD,O是對角線交點,∴OA=OC,易證△AOF≌△COE,∴OE=OF,CE=AF,設CE=x,則AF=x,FB =4-x,OE=y,則EF=2y,∴由周長=3+x+2y+4-x=9.6,∴y=1.3即OF=1.3
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