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y=1-cos^2(x)-cosx+3 =-cos^2(x)-cosx+4 令t=cosx,將x的範圍帶進去求出t的範圍 主要是你題中給的x的範圍有問題, 如果x屬於[π/6,2π/3),則t屬於(-1/2,√3/2],函數可化為: y=-t^2-t+4 =-(t+1/2)^2+17/4 所以y的範圍是((4+2√3)/4,17/4)
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