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設y=kx+b,經過(1,2) 2=k+b b=2-k y=kx+2-k 與x軸交點((k-2)/k,0) 與y軸交點(0,2-k) (k-2)/k×(2-k)=9 k²;+5k+4=0 k=-1,k=-4 y=-x+3 y=-4x+6
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