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定積分即是面積.假設被積函數是f(x),積分區間為(a,b) 將積分區域劃分n份,n趨向於無窮大,則每一小份寬度為(b-a)/n 在每一份足够小的時候,積分面積可近似為一個矩形,面積s=(b-a)/n*f(x) 再將這些矩形的面積加起來就好了故為: i=1——>n(a-b)/n*f(a+(b-a)/n*i),就是求上式和的n趨向無窮大的極限
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