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y=x²; 求導 y'=2x 直線2x-6y+5=0斜率為1/3 所以切線的斜率為-3 當2x=-3得x=-3/2 帶入y=x²; 得y=9/4 所以 切點座標為(-3/2,9/4) 切線為 y-9/4=-3(x+3/2) y=-3x-9/2+9/4 y=-3x-9/4
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