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由抛物線方程y^2=4x,得抛物線的準線方程是:x=-1,抛物線的焦點座標是(1,0).∴過抛物線焦點且傾斜角為45°的直線方程是y=(x-1)tan45°=x-1.∵A、B在直線y=x-1上,∴可設A、B的座標分別是(m,m-1)、(n,…
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