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單調.證明:(反證法)假設f(x)在[a,b]在不單調,即函數必有增有减,且函數連續則至少存在x1屬於[a,b],x2屬於[a,b],且x1不等於x2,使得:c=f(x1)=f(x2);設f(x)的反函數為g(x),則依據定義有g(c)=x1和g(c)=x2即x1=x2,此與…
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