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證明: ∵∠ABC=∠ADC=90° ∴⊿ABC和⊿ADC是直角三角形,AC為共斜邊, ∵M為AC的中點 ∴BM和DM分別為斜邊中線 ∴BM=DM=½;AC【直角三角形,斜邊中線等於斜邊的一半】 ∴⊿MBD是等腰三角形 ∵MN⊥BD根據三線合一,MN是底邊中線 ∴BN=ND
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