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設中間數為a,則第一個數為a-d,第三個數為a+d,a+(a-d)+(a+d)=12,得a=4 a(a-d)(a+d)=60,得d1=1,d2=-1,當d=1時,a+d=5,a-d=3當d=-1時,得a+d=3,a-d=5 綜上,這三個數分別為3,4,5
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