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因為:(b+c)/a=(a+b+c)/a-1 (a+c)/b=(a+b+c)/b-1 (a+b)/c=(a+b+c)/c-1 所以:2(a+c)/b=2(a+b+c)/b-2 =(a+b+c)×2/b-2 =(a+b+c)×(1/a+1/c)-2 =(b+c)/a+(a+b)/c
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