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∫[e,+∞]1/[x(lnx)^p] dx =∫[e,+∞](lnx)^(-p)dlnx = 1/(lnx)^(p-1)* 1 /(-p+1) = 0 - 1/(lne)^(p-1)* 1/(1-p) = -1/(1-p) = 1/(p-1)
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