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作AD垂直於BC交BC於D PA^2=AD^2+PD^2(畢氏定理) BD=CD(三線合一) PB*PC=BD-PD)(CD+PD) =(BD-PD)(BD+PD) =BD^2-PD^2 =AB^2-AD^2-(AP^2-AD^2) =AB^2-AP^2 =36-16=20
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