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設十比特數位為x,個位數位為y 則這個二位數為y+10x,交換二個數位後為10Y+x 根據題意,可得 y+10x=x+y+9 10y+x=y+10x+27 解這個方程組可得 x=1 y=4 這個兩位數為14
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