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作AE⊥BC於點E 設DE=x 則AE^2=5^2-x^2=7^2-(3+x)^2 即5^2-x^2=7^2-(3+x)^2 解得:DE=2.5 在Rt△AED中,根據畢氏定理AE=2.5√3 ∵∠B=45° ∴AB=√2AE=2.5*√6
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