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1+a+b≤ab≤[(a+b)/2]² ∴1+a+b≤(a+b)²/4 ∴(a+b)²-4(a+b)-4≥0 解得:a+b≥2+2√2或a+b≤2-2√2 ∵a,b>0 ∴a+b≥2+2√2 當且僅當a=b=1+√2時a+b取得最小值2+2√2
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