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x^2-2(m+1)x+(m^2+2m+1)-2m-3=0 (x-(m+1))^2=2m+3 x=(m+1)±√(2m+3) x1^2+x2^2=2(m+1)^2+2(2m+3)=8 m^2+4m=0 m(m+4)=0 m=0或m=-4,其中m=-4時方程無解.所以m=0
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