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x=0,f(x)=1,即(0,1)是切點. 求導,f(x)的導數為-cosx/(1+sinx)^2,其在x=0的值為-1, 由導數的幾何意義,切線的斜率為-1. 由點斜式得,切線方程是x+y-1=0
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