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設a,b分別為兩條直角邊的長度,則a+b=8,那麼b=8-a,根據面積公式:S=1/2*a*b=1/2*a*(8-a)= -1/2(a-2)(a-2)+2,囙此當a,b分別為2和6時三角形的面積最大,且最大面積為2
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