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假如n個數中有一個是n的倍數,顯然成立 若沒有 則這n個數除n后的餘數是1,……,n-1 必有某兩個數的餘數相同,餘數是1和n-1的兩數之和必能整除n 所以對於任意n個自然數,其中必有一個數或若干個數的和是n的倍數
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