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Sn=nan-n(n-1) an=Sn-S(n-1)=nan-n(n-1)-(n-1)a(n-1)+(n-1)(n-2) 化簡得(n-1)[an-a(n-1)]=2(n-1) ①當n≠1時an-a(n-1)=2 數列{an}是以1為首項2為公差等差數列 an=a1+(n-1)d=1+2(n-1)=2n-1 當n≠1時an=2n-1
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