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由距離公式得d=|1*sinβ+(-√3)cosβ|/√(1²;+(-√3)²;)=|sinβ-√3cosβ-2|/2,而 sinβ-√3cosβ=2sin(β-π/3),囙此d的最大值為0.5*|-2-2|=2.
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