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由(x2−1x)n展開式的二項式係數之和為2n=32,求得n=5,可得(x2−1x)n展開式的通項公式為Tr+1=Cr5•(-1)r•x10-3r,令10-3r=4,求得r=2,則展開式中含x4的項的係數是C25=10,故選:A.
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