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奇數項有n項,是等差數列a1=6a(2n-1)=5(2n-1)+1=10n-4所以和=(6+10n-4)n/2=5n²;+n偶數項是等比數列a2=2a(2n)=2^(2n/2)=2ⁿ;q=2所以和=2(2ⁿ;-1)/(2-1)=2^(n+1)-2所以S2n=5n²;+n+2^(n+ 1)-2…
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