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2x2x+5−55x−2=1.2x(5x−2)(2x+5)(5x−2)−5(2x+5)(2x+5)(5x−2)=1,2x(5x−2)−5(2x+5)(2x+5)(5x−2)=1,10x2-14x-25=10x2+21x-10,-35x=15,x=-37,檢驗:把x=-37代入(2x-5)(5x-2)≠0,∴x=-37是原方程的解...
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