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求公共點坐標,即求交點坐標,交點坐標中(x,y)同時滿足以上兩個方程;\x0d所以可以聯立兩個方程,解出對應的x、y即可;\x0d3x+10y-25=0;可得y=(25-3x)/10;代入以下方程:\x0dX2/25+Y2/4=1;有x-6x+9=0;\x0d可解...
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