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A、《塞瓦定理》:O為△ABC內任一點,AO延交BC於D,BO延交AC於E,CO延交AB於F,則(AF/BF)•;(BD/CD)•;(CE/AE)=1,見圖4.證明:在△AOB中,OF分∠AOB,由《分角定理》→AF/BF=(sin∠AOF/sin∠BOF)•;(AO…
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