The following formulas are as follows: radical 16x; Radix A2 + 4; Radix 1 / X; Radix 2x 2 y, where the number of the simplest quadratic radical is () A、1 B、2 C、3 D 、4

The following formulas are as follows: radical 16x; Radix A2 + 4; Radix 1 / X; Radix 2x 2 y, where the number of the simplest quadratic radical is () A、1 B、2 C、3 D 、4

The simplest quadratic root is
Radical (a 2 + 4)
Just this one
So choose a, 1
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若根號三次下2x-1=-三次根號下5x+8，求x的平方

根號三次下2x-1=-三次根號下5x+8
根號三次下2x-1=三次根號下-5x-8
2x-1=-5x-8
7x=-7
x=-1
x的平方=1

x²+x-（a²-a）x²-5x+3 x²-2根號2x-3 3x²+4xy-y² 分解因式x²+x-（a²-a）x²-5x+3 x²-2根號2x-3 3x²+4xy-y²

x²+x-（a²-a）=x^2+x-a^2+a=x^2-a^2+（x+a）=（x+a）（x-a）+（x+a）=（x+a）（x-a+1）x^2-5x+3=x^2-5x+25/4+3-25/4=（x-5/2）^2-13/4=（x-5/2+√13/2）（x-5/2-√13/2）=[x-（5+√13）/2][x-（5-√13）/2]x^2-2√2x-3=（x-√2）^2…