It is known that two of the equations x ^ 2 - (log2 B + loga 2) x + loga B = 0 about X are - 1 and 2, and the values of real numbers a and B are obtained

It is known that two of the equations x ^ 2 - (log2 B + loga 2) x + loga B = 0 about X are - 1 and 2, and the values of real numbers a and B are obtained

The results of Weida theorem are as follows
log2(b)+loga(2)=-(-1+2)=-1
loga(b)=-1*2=-2
b=a^(-2)
log2(a^(-2))+loga(2)=-1
-2log2(a)+loga(2)=-1
Let t = loga (2)
-2/t+t=1
t^2-t-2=0
(t-2)(t+1)=0
T = 2, or - 1
(1) T = 2, loga (2) = 2, a ^ 2 = 2, a = radical 2, B = 1 / A ^ 2 = 1 / 2
(2)t=-1,loga(2)=-1,a^(-1)=2,a=1/2,b=1/a^2=4

Elden Ring Premiere

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