Given that a focus of hyperbola x2a2 − y2b2 = 1 coincides with the focus of parabola y2 = 4x, and the eccentricity of the hyperbola is 5, then the asymptote equation of the hyperbola is______ ．

Given that a focus of hyperbola x2a2 − y2b2 = 1 coincides with the focus of parabola y2 = 4x, and the eccentricity of the hyperbola is 5, then the asymptote equation of the hyperbola is______ ．

According to the meaning of the question, the focus coordinate of the parabola y2 = 4x is (1, 0) ∵ a focus of the hyperbola x2a2 − y2b2 = 1 coincides with the focus of the parabola y2 = 4x, ∵ C = 1 ∵ the eccentricity of the hyperbola is 5, ∵ CA = 5 ∵ a = 55 ∵ B2 = C2 − A2 = 45 ∵ B = 255 ∵ the asymptote equation of the hyperbola is y = ± Bax = ± 2x, so the answer is: y = ± 2x