(x->0)lim(x * sin1/x) = ? Is that zero or one? Personally, I worked out one. I'm based on the fact that when X - > 0, SiN x is equivalent to X. So I figured it out to be one.

(x->0)lim(x * sin1/x) = ? Is that zero or one? Personally, I worked out one. I'm based on the fact that when X - > 0, SiN x is equivalent to X. So I figured it out to be one.

X → 0, X is infinitesimal, sin1 / X is a bounded variable, the product of bounded variable and infinitesimal is infinitesimal
The answer is 0
lim[sin(1/x)]/(1/x)=1
The premise of this conclusion is 1 / X → 0, that is, X →∞, and the problem is x → 0