Given that the tangent equation of curve y = f (x) at point (1, f (1)) is x-2y + 4 = 0, then f (1) + F '(1)=______ .

Given that the tangent equation of curve y = f (x) at point (1, f (1)) is x-2y + 4 = 0, then f (1) + F '(1)=______ .

The tangent equation of ∵ y = f (x) at point (1, f (1)) is x-2y + 4 = 0, ∵ 1-2y + 4 = 0, the solution is y = 52, that is, f (1) = 52, the slope of tangent is k = 12, that is, f '(1) = 12, then f (1) + F' (1) = 52 + 12 = 3, so the answer is: 3