Find the tangent equation of point a [2,4] and tangent to circle C: [x-3] &# 178; + [Y-2] &# 178; = 1

Find the tangent equation of point a [2,4] and tangent to circle C: [x-3] &# 178; + [Y-2] &# 178; = 1

It can be seen from the graph that x = 2 is a tangent of a circle
Radius of center (3,2) r = 1
Let the slope of the other tangent be K
y-4=k(x-2) kx-y+4-2k=0
|3k-2+4-2k|=√(k^2+1)
k=-3/4
Tangent equation 3x + 4y-22 = 0