Through the point (2, - 3) to the circle (x-1) & # 178; + (y + 3) & # 178; = 1, the tangent line is introduced and the tangent equation is solved

Through the point (2, - 3) to the circle (x-1) & # 178; + (y + 3) & # 178; = 1, the tangent line is introduced and the tangent equation is solved

Let the tangent be K (y + 3) = X-2
After finishing, x-ky-3k-2 = 0
Because it is tangent, then the distance from the center of the circle (1, - 3) to the tangent is 1
d=|1+3k-3k-2|/√(k^2+1)=1
The solution is k = 0
So the tangent equation is x = 2