When x tends to zero, the denominator of square * sin (1 / x) of TaNx + X is 2x. What's the limit···

When x tends to zero, the denominator of square * sin (1 / x) of TaNx + X is 2x. What's the limit···

When x → 0
[tanx+x^2*sin(1/x)]/(2x)
→(1/2)[(tanx)/x+xsin(1/x)]
→(1/2)(1+0)
=1/2.
Note: | sin (1 / x)|