Let f (x) = | x-1| Tan (x-3) / (x-1) (X-2) (x-3) ^ 2, then f (x) is bounded a (0,1) B (1,2) C (2,3) d (3,4) in which of the following intervals

Let f (x) = | x-1| Tan (x-3) / (x-1) (X-2) (x-3) ^ 2, then f (x) is bounded a (0,1) B (1,2) C (2,3) d (3,4) in which of the following intervals

When X - > 2,3, the denominator tends to 0, the numerator is finite, so it is unbounded
When x is (0,1), Tan (x-3) is bounded, and when X - > 1, f (x) ~ - Tan (- 2) / (1-2) (1-3) ^ 2 is bounded
So you can only choose a