How many liters does a small car use for one kilometer

How many liters does a small car use for one kilometer

3 / 25 △ 3 / 2 = 2 / 25 (L)
A: 2 / 25 liter per kilometer

As shown in the figure, ad ‖ BC, EA bisection ∠ DAB, ab = AD + BC, indicating EB bisection ∠ ABC

Certification:
Extend AE and BC to intersect at point G
Because: AD / / BC
So: ∠ DAE = ∠ CGE
Because: AE is equal to DAB
So: ∠ DAE = ∠ BAE
So: ∠ DAE = ∠ CGE = ∠ BAE
So: ab = BG = AD + BC
So: BC + CG = AD + BC
So: ad = CG
Because: ∠ DAE = ∠ CGE, ∠ DEA = ∠ CEG (equal to vertex angle)
So: △ DAE ≌ △ CGE (corner side)
So: AE = Ge
So: e is the midpoint of Ag
Because: △ ABG is an isosceles triangle, ab = BG
So: be is the vertical bisector of Ag at the bottom
So: be is equal to ABC

A bus and a car are running from two places with a distance of 600 kilometers at the same time. They meet four hours later. The speed ratio of the bus to the car is 2:3. What are the speeds of the bus and the car?

The speed of passenger car: 600 ／ 4 × 22 + 3, = 600 ／ 4 × 25, = 60 (km / h). The speed of passenger car: 600 ／ 4 × 32 + 3, = 600 ／ 4 × 35, = 90 (km / h). Answer: the speed of passenger car is 60 km / h, the speed of passenger car is 90 km / h

(2a-3b) (2a + 3b) (the fourth power of 4A + the square of 9b)=

(2a-3b) (2a + 3b) (the fourth power of 4A + the square of 9b)
=(the second power of 4A - the square of 9b) (the fourth power of 4A + the square of 9b)
=The sixth power of 16A + 36a & # 178; B & # 178; - 36a's fourth power B & # 178; - 81b's fourth power

A batch of goods weighing 26 tons will be transported to a certain place. The owner of the goods is going to rent two kinds of trucks from the automobile transportation company. It is known that he has rented such trucks twice in the past
The first time, the second time
3 class a goods vehicles
Type B goods vehicles (vehicles) 28
Cumulative tonnage (ton) 17 32
The owner of the goods wants to make this batch of goods both loaded and just full of the rented vehicle. Please give us your reasons

Type B freight car load = (32-17) / (8-2) = 2.5 (T)
Load of class a freight vehicle = (17-2 * 2.5) / 3 = 4 (T)
A batch of 26 tons of goods to be shipped to a place, just full of rental vehicles can do, each rental 4 cars
The total amount of freight transported by 4 rented vehicles is 2.5 * 4 + 4 * 4 = 26 (tons)

The equation of a circle passing through the point P (- 4,3) with its center on the straight line 2x-y = 1 = 0 and radius 5

The above two methods are too complicated
Write the equation according to the radius
(X-A)^2+(Y-B)^2=25
If the center of the circle (a, b) is on the line, 2a-b = 1, B = 2a-1
Substituting (- 4,3) (- 4-A) ^ 2 + (3 - (2a-1)) ^ 2 = 25
A is obtained by solving the equation, and B is obtained by using B = 2a-1
Answer (x-1) ^ 2 + (Y-3) ^ 2 = 25 or (x + 1) ^ 2 + (y + 1) ^ 2 = 25
Analytic geometry needs to be tried by hand

There is a batch of goods on the freight station, which can be transported by car a in 10 hours and by car B in 15 hours. Both cars can transport the goods at the same time. After transporting the goods, car a will transport 42 tons more than car B. how many tons of this batch of goods in total?

It's necessary to finish the shipment
1 ÷ (1 / 10 + 1 / 15) = 6 (hours)
It's in car a
1 / 10 × 6 = 3 / 5
B: it's in the car
1 / 15 × 6 = 2 / 5
The goods are in total
42 (3 / 5-2 / 5) = 210 (tons)

It is known that the solutions of the equations 4x-1 = 3x-a and 3x + 1 = 6x-2a about X are opposite to each other, and the value of a is obtained

4x-1=3x-a
x=1-a
3x+1=6x-2a
3x=2a+1
x=(2a+1)/3
On the contrary, 1-A = - (2a + 1) / 3
3-3a=-2a-1
So a = 4

It is necessary to transport 420 tons of yellow sand to the factory, one-third of the total amount at one time and two fifths of the total amount at the second time. How many times will it take to transport it?

I don't quite understand. I'll take a look at you, right
One time transport 420x1 / 3 = 140
Secondary transport 420x2 / 5 = 168
420-140-168 = 112 left
It'll be finished once more
You're not sure how to calculate the quantity of each vehicle

Given that the area of the triangle formed by the line L1: y = 2x-6 and L2: y = - 2x + m and the Y axis is 8, the analytic formula of the line L2 is obtained

L1: the intersection of y = 2x-6 and Y axis is (0, - 6);
L2: the intersection of y = - 2x + m and Y axis is (0, m);
The intersection of L1: y = 2x-6 and L2: y = - 2x + m is ((M + 6) / 4, (M-6) / 2)
The enclosed area s = | m + 6 | &# 178 / 8 = 8
Then: M + 6 = ± 8
So, M = - 14 or M = 2
Therefore, the analytic expression of line L2 is y = - 2x-14 or y = - 2x + 2