If limx → 3 (x ^ 2 + ax + b) / (x-3) = 1, find the value of a and B

If limx → 3 (x ^ 2 + ax + b) / (x-3) = 1, find the value of a and B

The denominator limit is 0
The limit is equal to one
So the molecular limit is zero
That is, the molecule has a factor x-3
Let molecule = (x-3) (x + C)
Then the original formula = x + C
Limit = 3 + C = 1
c=-2
So x ^ 2 + ax + B = (x-3) (X-2)
So a = - 5, B = 6

Given that a and B are constants, limx → 2 (AX + b) / (X-2) = 2, find the value of a and B
Can we use the law of Robida?

a/1=b/(-2)=1
∴a=1 b=-2

Given that f (x + 1) = x square - 4. The sequence {an} satisfies A1 = f (x-1). A2 = - 3 / 2, A3 = f (x) find: X, an, A2 + A5 + A8 + +The value of A26
Come on, come on, come on
thank you
o(∩_ ∩)o...

Let f (x) be an arithmetic sequence? (1) ∵ f (x + 1) = (x + 1-1) 2-4 = [(x + 1) - 1] 2-4, ∵ f (x) = (x-1) 2-4. ∵ A1 = (X-2) 2-4, A3 = (x-1) 2-4. And a1 + a3 = 2A2, the solution is x = 0 or x = 3. (2) ∵ A1, A2, A3 are 0, - / 2, - 3 or - 3, - 3 / 2, 0, ∵ a respectively

F (x + 1) = x ^ 2-4 in the arithmetic sequence A1 = f (x-1) A2 = - 3 / 2 A3 = f (x) find x find an A2 + a3 +. + A26=

From F (x + 1) = x ^ 2-4, we know that A1 = f (x-1) = (X-2) ^ 2-4, A3 = f (x) = (x-1) ^ 2-4
From 2A2 = a1 + a3, the solvable is: x = 0, x = 3
1. When x = 0, A1 = 0, A2 = - 1.5, then an = - 1.5n + 1.5, S26 = - 4875.5
2. When x = 3, A1 = - 3, A2 = - 1.5, then an = 1.5n-4.5, S26 = 448.5

Calculation: power 0 of 2A power 0 of - (2a) a is not equal to 0

0 power of a = 1 (2a) = 1
Power 0 of 2A power 0 of 2A = 2-1 = 1

The solution of the equation (2m + 3) x = m square + 1 (M is not equal to - 3 / 2) of X is_______

x=(m^2+1)/(2m+3)

The solution of the equation about X (square of m-1) x = square of m-m-2 (square of M is not equal to 1) is

(square of m-1) x = square of m-m-2
（m-1）（m＋1）x=（m＋1）（m-2）
Because the square of M is not equal to 1
therefore
M ≠ 1 and m ≠ - 1
therefore
x=（m-2）/（m-1）

Judge whether x = 3, y = 1 is the solution of binary linear equations 2x-y = 5, 3x + y = 10, and explain the reason

x=3,y=1
So 2x-y = 6-1 = 5
3x+y=9+1=10
So both equations hold
So it's the solution of the system of equations,

If the solution of the bivariate linear equation 3x ay = 16,2x + by = 15 about X, y is x = 7, y = 1, by analogy, I believe you can solve the following equations about X, y simply
3(x+y)-a(x-y)=16
2(x+y)+b(x-y)=15

Let x = x + y be large
Big y = X-Y
Then 3 (x + y) - A (X-Y) = 16
2(x+y)+b(x-y)=15
Replace with
3X-aY=16
2X+bY=15
Known by
X = 7
Big y = 1
That is, large x = x + y = 7
Big y = X-Y = 1
Solving binary linear equations
We get x = 4
y=1

General solution of differential equation y '' - y = Xe ^ 2x

The characteristic equation is: x ^ 2-1 = 0, the characteristic root is 1, - 1 is: Y1 = C1E ^ x + c2e ^ (- x) let the special solution y * = (AX + b) e ^ (2x) y * '= (2aX + A + 2b) e ^ (2x) y * "= (4ax + 4A + 4b) e ^ (2x) be substituted into the original equation to get: 3ax + 4A + 3B = x, 3A = 1,4a + 3B = 0, a = 1 / 3, B = - 4 / 9, so the general solution y = Y1 + y * = C1E ^