Given that a is a root of the equation x-x-1 = 0, find the value of cube-2a + 2007 of A

Given that a is a root of the equation x-x-1 = 0, find the value of cube-2a + 2007 of A

a^2-a-1=0
a^2-a=1
a^3-a^2 -a = 0
a^3-2a+2007
=(a^3-a^2-a)+a^2-a +2007
=0+1+2007
=2008

Given that a and B are two parts of the equation x + X-1 = 0, find 1 / 2 of a + 2A + B

If the sum of solutions of two equations 2x + a = 3,2a-x = 6 of X is twice the difference, then a =?

3

It is known that the solution of the equation 2x-1 = x + a about X is the solution of the equation (x + a) = 3 - (2a + x) / 5. Find the value of A
It is known that the solution of the equation 2x-1 = x + a about X is the solution of the equation (x + a) / 2 = 3 - (2a + x) / 5. Find the value of A
I'm sorry to miss "2".

2x-1=x+a
2x-x=a+1
The solution is: x = a + 1
a+1+a=3-(2a+a+1)/5
10a+5=15-3a-1
10a+3a=15-1-5
13a=9
a=9/13

For a pile of coal, 600 tons were transported in the first day, just one sixth of the coal in the station. The ratio of the coal transported in the second day to the total amount of this pile of coal is 1:5. How many tons were transported in the second day

600 divided by 6 / 1 = 3600 (tons)
1+5=6
3600 * 6 / 1 = 600 (T)
600 + 120 = 720 (tons)

Given x > 0, verify (radical √ 1 + x) b > 0, C > d > 0, verify √ (A / D) > √ (B / C)

1、1+x-(1+x/2)^2
=1+x-1-x-x^2/4
=-x^2/4
x>0
So x ^ 2 > 0
-x^2/40,1+x/2>0
0d>0
Therefore, 1 / d > 1 / C
Therefore, a / d > b / C
So, the root sign (A / D) > the root sign (B / C)

The speed ratio of car a and car B is 5:8. The two cars start from a and B at the same time and meet at 24 kilometers away from the midpoint. How many kilometers are there between the two places? [hint: when a and B meet, the distance ratio and speed ratio are the same]. When the driving time is the same, the distance ratio remains unchanged, and the speed ratio is the same

A: the distance between the two places is 208 km

What is the solution set of the system of inequalities with 1 x + 1 > 0,2-x ≥ 0?

1 / 3 x + 1 > 0
1/3x+1>0
1/3x>-1
x>-3
2－x≥0
2≥x
The solution set is - 3

On a map with a scale of 1:4000000, the distance between a and B is 20cm. Buses and trucks start from a and B at the same time and run in opposite directions,
It is known that the speed of passenger cars is 75 kilometers per hour, and the speed ratio of passenger cars and freight cars is 15:17. How many hours do two cars meet?

Distance 20x4000000 = 8000000cm = 800km
Truck 75x17 / 15 per hour = 85 km
The time of meeting is 800 (85 + 75) = 800 (160) = 5 hours
If you don't understand this question, you can ask,

IAI = IBI = 1, a is perpendicular to B, (2a + 2b) is perpendicular to (ka-4b), find the real number K

From (2a + 2b) ⊥ ka-4b,
Then (2a + 2b) · (ka-4b) = 2kA & sup2; - 8b & sup2; + 2 (K-4) AB = 0,
∵|a|=|b|=1,ab=0,
∴2k-8=0,
∴k=4.