For the function f (x), among all the constants m that hold f (x) ≥ m, we call the maximum value in m the infimum of function f (x), then the infimum of function f (x) = x2 + 1 (x + 1) 2 is () A. 14B. 12C. 1D. 2

For the function f (x), among all the constants m that hold f (x) ≥ m, we call the maximum value in m the infimum of function f (x), then the infimum of function f (x) = x2 + 1 (x + 1) 2 is () A. 14B. 12C. 1D. 2

F (x) = x2 + 1 (x + 1) 2 ｛ f '(x) = 2 (x2 − 1) (& nbsp; X + 1) 4 = 0 the solution is x = ± 1 when x ∈ (- ∞, - 1), f' (x) > 0 when x ∈ (- 1,1), f '(x) < 0 when x ∈ (1, + ∞), f' (x) > 0 ｛ when x = 1, the function takes the minimum value, which is also the minimum value 12, so B is selected

If the equation x ^ 2-mnx + m + n = 0 has integer roots, and m and N are positive integers, find m and n

Let two roots be a and B
a+b=mn,ab=m+n
We find that AB is also a positive integer~
If m, n > = 2, then M + n

Given two positive integers m and N, m divided by n = 3, then (m, n) = () [M, n] = ()

Given two positive integers m and N, m divided by n = 3, then (m, n) = (n) [M, n] = (m)