AB has only prime factors 2 and 3, and their least common multiple is 144 AB has only prime factors 2 and 3, and their least common multiple is 144. Given that a has 12 divisors and B has 10 divisors, what is the sum of AB?

AB has only prime factors 2 and 3, and their least common multiple is 144 AB has only prime factors 2 and 3, and their least common multiple is 144. Given that a has 12 divisors and B has 10 divisors, what is the sum of AB?

A: 72 (approximate: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72)
B: 48 (approximate: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48)
72+48=120

A = 2 × a × B, B = 3 × B × B. A, the greatest common factor of B is () and the least common multiple is ()

The greatest common factor is B
The least common multiple is 6ab

If the three sides of a triangle are 2Mn, M & sup2; + n & sup2; and M & sup2; - N & sup2;, where m, n are positive integers and M > n. prove that the triangle is a right triangle

Right angle of syndrome:
（2mn）^2 +(m^2-n^2)^2=(m^2+n^2)^2
So it's a right angle