How much ah does 1kVA equal or how much KVA does 1Ah equal! It's better to have a formula.

How much ah does 1kVA equal or how much KVA does 1Ah equal! It's better to have a formula.

A. H = ampere hour, the unit to measure the capacity of power storage equipment, can be simply understood as: 1A. H means that the power storage equipment can work continuously for 1 hour when the power supply current intensity is 1a. KVA = 1000VA refers to the apparent power, while w or kW refers to the active power. In a period of time, the device may consume active power or reactive power, such as resistance only consumes active power, P = xxui, Capacitors and inductors (not consuming active power components) only consume reactive power P = xxvar. If the existing resistors and capacitors (or inductors) consume power P = xxva, different units in the circuit represent different power
Given the total power KVA, how to calculate the current and find the calculation formula
KVA / 1000 = VA, VA / u = A. if it is three-phase electricity, divide it by 1.73 to get the rated current
What is 1kVA equivalent to
That is, one kilowatt hour is equal to one degree, KVA is often used to label power supply equipment such as transformer, and kW is often used to label various electrical equipment. Because of the influence of transmission and power factor, 1kVA power supply often can not provide 1kW power
How much kW is one a?
Ha ha. You are short of a voltage (V) parameter in this question, because 1kW = 1000VA, so 1000A = 1kW / v. if you don't tell the voltage parameter, there are infinitely many answers. A is the basic unit of current, kW is the power, and the unit power is the efficiency of doing work in unit time (usually seconds), such as one in one second
A cuboid shaped copper bar is 2.5 meters long and its cross section is a square with a side length of 4 cm. It is known that the weight of copper per cubic decimeter is 8.9 kg. How about the weight of this copper bar? Please explain the basic principle and its formula. Thank you for saying that volume × density = mass. Please give an example
Density is the mass of an object per unit volume
2.5 m = 25 decimeters, 4 cm = 0.4 decimeters
Volume: 0.4 × 0.4 × 25 = 4 cubic decimeter
Weight: 8.9 × 4 = 35.6kg
Mass = 0.04 * 0.04 * 2.5 * 8.9 * 1000, the basic principle is mass = volume * density, density means the mass of the object per unit volume. For example, 8.9kg/dm3 means that the mass of copper per cubic decimeter is 8.9kg.
Cross sectional area: 0.5 × 0.5 = 0.25 square decimeter volume: 0.25 × 15 = 3.75 cubic decimeter weight: 3.75 × 8.9 = 33.375 kg
How to calculate the area of the bottom of a cylinder
PI times the square of the base radius
PI times the square of (diameter divided by 2)
S=πRR
The square of the radius times the height of the pie
Square of π * radius
3.14XrXr
Pai is the PI R2 {is the square}, that is to find the area of the circle
The area of the bottom is also a circle. The area of the circle is equal to the square of the circumference times the radius.
Example: radius 3 cm, height 4 cm, what is the bottom area?
3.14 × 3 × 3 = 28.26 (CM)
What's the diameter, what's the height, what's the area?
4 △ 2 = 2 (CM) 3.14 × 2 × 2 = 12.56 (CM)
Hope to adopt, thank you!
If the resistor R1 and R2 are connected in series at both ends of the same power supply, the power consumed by R1 is P1, and the current of the main circuit is 0.9A. If the resistor R1 and R2 are connected in series at both ends of the same power supply, the power consumed by R1 is P1 ′ = P19, then the current through resistor R2 is 0.9A______ A．
The fixed resistance R1 and R2 are connected at both ends of the power supply with constant voltage, the voltage at both ends of R1 is u, the current is I1, and the consumed electric power is P1; the resistance R1 and R2 are connected in series at both ends of the same power supply, the voltage at both ends of R1 is U1 ', the current is I1', and the consumed electric power is P1 '; from P1' = 19p1, according to P = I2R = u2r
A "220V 1000W" electric heater, energized at rated voltage for 15 minutes,
(1) How much heat is produced?
(2) If 70% of the heat is absorbed by 75 kg water at 30 ℃, how much ℃ does the water temperature rise to at 1 standard atmospheric pressure
(1)W=1000W×15×60S=900000J
(2)4200J/kg.℃×75kg×(T-30℃)=70%W
T=32℃
1800 grams in a cuboid copper bar. It is 2 meters long and its cross section is a square with a side length of 30 cm. 1. How many kilograms of copper per cubic decimeter
2. What's the volume of a 7.2 ton copper bar
1. The bottom area is 30 * 30 = 900 square centimeter = 9 square decimeter
Therefore, the height of copper per cubic decimeter is 1 / 9 decimeter, accounting for 1 / 180 of the total length
So the weight is 1800 * 1 / 180 = 10g
2. The original cuboid volume is 30 * 30 * 2 △ 10000 = 0.18 cubic meters
In other words, 0.18 cubic meters of copper weighs 1800 grams
Therefore, the volume of copper per ton is 0.18 △ 1800 * 1000000 = 100 cubic meters
So the volume of 7.2 tons of copper is 7.2 * 100 = 720 cubic meters
1800 g = 1.8 kg
30 cm = 0.3 M = 3 decimeter
2 m = 20 decimeters
Then volume = 20 * (3 * 3) = 180 cubic decimeter
be
The weight of copper per cubic decimeter is 1.8/180 = 0.01kg
2) 7.2 tons = 7200 kg
Then volume = 7200 / (0.01) = 720000 cubic decimeters = 720 cubic meters
1. 2 decimeters = 20 meters
30 cm = 3 decimeters
The volume of copper rod is 3 * 3 * 20 = 180 cubic decimeter
So the density is 1800 / 180 = 10 g / cm3
That is, the weight of copper per cubic decimeter is 10 g = 0.01 kg
2. 7.2 tons = 7200 kg
Volume = 7200 / 0.01 = 720000 cubic decimeters = 7200 cubic meters
Formula of area of cylinder bottom
S=πr^2
R is the radius of the bottom circle