What is 1kVA equivalent to

What is 1kVA equivalent to

1kVA is the unit of capacity (power)
Ampere is the unit of current
The unit is different and cannot be converted
If 1ka = 1000A
one thousand
What is 1p equal to
"Pi" is a unit of power, which means one horsepower = 750W. For domestic air conditioners, it is indeed a foreign practice to use "Pi" to measure. Here "Pi" refers to the input power. Converted into the w expressed by the output power in our country, one "Pi" is equivalent to 2200W -- 2600w. Therefore, it is too rough to use "Pi" to measure, which leads to the so-called "big one", Generally speaking, the cooling capacity is 2300-2500w. The input power is about 800W
The value of British horsepower is not quite the same. There are metric horsepower and British horsepower. I remember that the value of British horsepower is a little bit (09-01 12:32 reply article) sylvan
Check the refrigeration Manual: 1 metric horsepower (PS) = 735.5w, 1 British horsepower (HP) = 745.7w (08-16 15:41 reply article) sylvan
Here's what I learned: one piece is about 750W. However, in actual engineering, several pieces are just a general statement. Therefore, it's more scientific to look at the name plate of the air conditioner
Unit Joule / mol and Joule / kg
If a 5 ohm resistor R1 and a 10 ohm resistor R2 are connected in series to a 15 V circuit, the power consumed by R1 is
If R1 and R2 are connected to another circuit, the electric power consumed by R1 is 10W, then the electric power consumed by R2 is 10W
P=IU
Question 1: if R1 is divided into 5V and the current is 1a, then R1 power is 5W,
Second, the voltage of R1 is the same as that of R2, so the current of R1 is twice that of R2, so the power is also twice that of R2, and the power of R2 is 5W
Total resistance: r = R1 + R2 = 5 + 10 = 15
Current: I = u / r = 15 / 15 = 1.0
P1 = I^2R1 = 1.0*5 = 5 W
P2 = I^2R2 = 1.0*10 = 10 W
First question:
Total resistance: r = R1 + R2 = 5 + 10 = 15 (Ohm)
Current: I = u / r = 15 / 15 = 1.0 (a)
P1 = I^2R1 = 1.0*5 = 5 W
Second question:
Known P1 = 10W
P1=U1*U1/R1 U1=U2
P2=U2*U2/R2=P1*R1/R2=10*5/10=5W
R1 p=UI
I=U/R R=R1+R2=5+10=15
U=5A I=1A P=1A*5V=5W/S
Second question
U1=U2
So the current of R1 is twice that of R2, so the power is twice that of R2, and the power of R2 is 5W.
How much heat does a "200V 1000W" electric heater produce when it is electrified at rated voltage for 15 minutes?
Power P = 1000W
Heat q = Pt = 1000x15x60 = 900000j
1000 * 15 * 60 = 900000 joules
Why do metal elements with large atomic weight have less density than those with small atomic weight
The density not only depends on the atomic weight, but also depends on the packing of metal atoms. Metal crystals have three kinds of lattice: body centered cubic, face centered cubic and hexagonal close packed. Even for the same kind of atoms, the density will be different if the packing is different
The letter formula of the area of the cylinder base
Side area = perimeter * height = radius * 2 π
Height * square area = 2
Surface area = 4 π * square of radius + 2 π * height
Cone volume = 1 / 3 * 2 π * square of radius * height
Cylinder side area: S = 2 π RH, where R is the bottom radius and H is the height of the cylinder
Volume: v = π h * (R ^ 2)
π = 2 π (r = 2)
Cone volume: v = 1 / 3 π h * (R ^ 2)
I think you should first make clear their side expansion. The side expansion of a cylinder is a rectangle, in which the length is the circumference of the bottom surface and the width is the length of the generatrix, that is, the height of the cylinder. The side area of a cone is very good. The side expansion of a cone is a sector, and the arc length is the circumference of the bottom surface
Side area: bottom perimeter × height volume: bottom area × height surface area: sum of side area + sum of bottom area × 2 volume formula of cone: bottom area × height × 1 / 3
Cylinder side area: bottom perimeter x height the surface area of a cylinder is: bottom perimeter times height plus bottom area times two
Volume of cylinder: base area multiplied by height volume of cone: base area multiplied by height multiplied by one third
There are two fixed value resistors, R1 = 120 ohm and R2 = 24 ohm, which are connected in series to a power supply. The voltage ratio of both ends of R1 and R2 is -; the electric power consumed by R1 and R2
If connected in parallel to the same power supply, the ratio of current passing through R1 and R2 is -; the ratio of electric power consumed by R1 and R2 is -
In the series circuit, the current is equal everywhere. According to the formula: u = I * r, the voltage ratio is equal to the resistance ratio. According to the formula P = UI = I * I * r, the power ratio is equal to the resistance ratio. Therefore, the current ratio of R1 and R2 is 1:1, and the power ratio is 5:1. If R1 = 12, the corresponding ratios are 1:1 and 1:2 respectively. In the parallel circuit, the voltage is equal, and the voltage is equal
I'm sorry, R1 is wrong, R1 = 12,. Please help me again
An electric heater draws 1000W power from the power supply of 220V. If the electric heater is connected to the power supply of 100V, the power drawn is
According to r = u ^ 2 / P1 = 220 ^ 2 / 1000 = 48.4 Ω,
P2 = u ^ 2 / r = 100 ^ 2 / 48.4 = 206.6 W
1000 watts! Energy is conserved
One
According to w = u & # 178 / R, r = u & # 178 / w = 220 & # 178 / 1000 = 48.4 Ω;
According to the constant resistance of electric heater, if connected to 100V, w = u & # 178 / r = 100 & # 178 / 48.4 = 206.6w
Zero
Why do some metals have high atomic weight but low density
For example, copper 63.5, zinc 65
The density of Cu is 8.9 and Zn is 7.14
Atomic weight is the property of metal atoms, and density is a physical property of metal. These are two concepts
Density is related to mass volume, which is determined by the crystal structure of metal
That is to say, the gap of zinc crystal structure is larger than that of copper, so the density is smaller