From natural numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, one number, two numbers, three numbers can be taken each time 9 numbers, first find the sum of the numbers taken out each time, and then find the sum of all the sums, please find out how much the sum is?

From natural numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, one number, two numbers, three numbers can be taken each time 9 numbers, first find the sum of the numbers taken out each time, and then find the sum of all the sums, please find out how much the sum is?

From the above analysis, according to the principle of multiplication, 3 is taken out 28 times, that is 256 times +8 + 9) × 256 = 45 × 256 = 11520. A: the total is 11520
Three continuous natural numbers, the first number is 7 / 8 of the second number, find the second natural number is ()
Are the three natural numbers 7, 8 and 9 respectively? The second one is 8
Eight
It's eight.
X times of 8, x > 0
In a factory, the ratio of the number of people in workshop a and workshop B is 4:3. Due to the need of work, 10 people are transferred from workshop a to workshop B. at this time, the number of people in workshop B accounts for 24% of the number of people in the two workshops. How many people are there in workshop B now?
A: there are 70 people in workshop B now
There are three numbers a, B and C. the number a is three times of the number B, and the number B is two times of the number C. We know that the sum of the three numbers is 36. What are the solutions of these three equations
Let C be x, B be 2x and a be 6x
2x+6x+x=36
X=4
The number C is 4, the number B is 8, and the number a is 24
Let C be X
x+2x+2x×3=36
X=4
B: 2 × 4 = 8
A: 8 × 3 = 24
Let C be x, B be 2x, and a be 6x
x+2x+6x=36
9x=36
X=4
C is 4, B is 2x4 = 8, a is 6x4 = 24
The ratio of people in workshop a and workshop B is 3:5. If 10 people are transferred to workshop B, now the ratio of people in workshop a and workshop B is 4:7. How many people are there in workshop a?
A: there were 120 people in workshop a
If the number a is 36, the number B is 4 more than the sum of the two numbers a and C, and the number C is 13 of the sum of the two numbers a and B, find the sum of the three numbers a, B and C
Let B and C be the sum of two numbers (a, B, c) and (B, c) respectively
The ratio of people in workshop a and workshop B is 3:5. If 10 people are transferred to workshop B, now the ratio of people in workshop a and workshop B is 4:7. How many people are there in workshop a?
A: there were 120 people in workshop a
The average number of a, B and C is 36; the average number of B and C is 30; the average number of a and C is 32
The average of a and B is 36; the average of B and C is 30; the average of a and C is 32
The average of a, B and C = (36 + 30 + 32) / 2 = 49
A: 38 B: 34 C: 26 I don't know what you want to know?
A + B = 36 * 2 = 72
B + C = 30 * 2 = 60
A + C = 32 * 2 = 64
So: a + B + C = (72 + 60 + 64) / 2 = 98
A: 98-60 = 38
B: 98-64 = 34
C: 98-72 = 26
If 24 people are transferred from workshop a to workshop B, then Party A is 3 / 4 of workshop B. how many people are there in workshop a?
The total number of Party A and Party B has not changed, with the total number of Party A and Party B as the unit of 1
A used to be 3 / 5 of the total
If 24 people are transferred from workshop a to workshop B, then 3 / (4 + 3) = 3 / 7
24 (3 / 5-3 / 7) = 140
40 × 3 / 5 = 84 persons
A: there were 84 people in workshop a
Solution: if the total number of people in the two workshops is x, then there are 3 / 5x people in workshop a and (1-3 / 5) x = 2 / 5x people in workshop B
3/5x-24=(2/5x+24)×3/4
3/5x-24=3/10x+18
3/5x-3/10x=24+18
x=42÷3/10
x=140
A: 140 × 3 / 5 = 84 persons
B: 140 × 2 / 5 = 56 people
The sum of a, B and C is 59 more than C, the sum of B and C is 49 more than a, and the sum of a and C is 85 more than B
The number C is: (59 + 49 + 85-59) △ 2, = 134 △ 2, = 67; the number a is: (59 + 49 + 85-49) △ 2, = 144 △ 2, = 72; the number B is: (59 + 49 + 85-85) △ 2, = 108 △ 2, = 54; a: the number a is 72, the number B is 54, and the number C is 67