There are three continuous natural numbers a, a + 1 and a + 2, which are just multiples of 9, 8 and 7 respectively. What is the smallest number among these three natural numbers/

There are three continuous natural numbers a, a + 1 and a + 2, which are just multiples of 9, 8 and 7 respectively. What is the smallest number among these three natural numbers/

A number can be divided by nine
Divided by 8, the rest is 7
Divide by 7 and leave 5
This number plus 9 is the common multiple of 8 and 9
That is, a + 9 is divided by 72
A + 9 is exactly divisible by 7
So a + 9 is the least common multiple of 7,8,9
A+9=7*8*9=560-56=504
A=495
The smallest of the three natural numbers is 495
Through verification, the answer is correct
Four hundred and ninety-five
a=9m
a+1=9m+1=8n n=(9m+1)/8=(8m+m+1)/8=m+ (m+1)/8
a+2=9m+2=7p p=(9m+2)/7=(7m+2m+2)/7=m+2(m+1)/7
If a + 1 and a + 2 are natural numbers, then M + 1 should be divisible by 7 and 8 at the same time, and the least common multiple of 7 and 8 is 56
m+1=56
m=55
a=9m=55×9=495
The smallest of the three natural numbers is 495.
Three continuous natural numbers, the first number is 78 of the third number, finding the second natural number is 78______ .
The second number is: 16-1 = 15, so the answer is: 15
The average number of a, B and C is 48. A is twice the number of B. C is 12
48 times 3 = 144
144-12 = 132 [Party A and Party B]
132 divided by (2 + 1) = 44 [b]
132-44 = 88 [a]
The number of people in workshop a is two fifths of that in workshop B. later, the number of people in workshop a increased by 20 and that in workshop B decreased by 35. At this time, the number of people in workshop a is seven ninths of that in workshop B
How many workers are there in each workshop?
This problem can be solved by equation
1. Suppose the number of people in workshop a is 2x at first, then the number of people in workshop B is 5x at first
2. After the change, the number of workshop a is 2x + 20, and workshop B is 5x - 35
3. According to the proportion in the title, the equation can be solved
（2X+20）/（5X-35）＝7/9
The solution is x = 25
4. So now the number of people in workshop a = 2 * 25 + 20 = 70, the number of people in workshop B = 5 * 25 - 35 = 90
The sum of the three numbers of a, B and C is 26. The number of a is one more than the number of B. the sum of two times the number of a and C is 18 more than the number of B. find these three numbers
Let B be x, a x + 1
2 (x + 1) + C = x + 18
So C = (x + 18) - 2 (x + 1)
So x + 1 + X + (x + 18) - 2 (x + 1) = 26
2x+1+x+18-2x-2=26
x+17=26
X=9
x+1=10
(x+18)-2(x+1)=7
A: a 10, B 9, C 7
Number C + number B: 18-1 × 2 = 16
Number A: 26-16 = 10
Number B: 10-1 = 9
C: 16-9 = 7
The answer on the first floor is very detailed.
Let the three numbers be x, y, Z respectively
The equation x + y + Z = 26 can be obtained
X-1=Y
2X+Z-Y=18
The solution is x = z = 9
Y=8
There are 120 workers in workshop a and workshop B, of which workshop a accounts for 2 / 5 of the total number of workers. Later, workshop B transferred people from outside. At this time, the ratio of the number of workers in workshop a and workshop B is
4: 7. How many people are there in workshop B now?
A = 120 × 2 / 5 = 48 persons
Now the total number of people = 48 × (4 + 7) △ 4 = 132
(B + 7) = 132 × 7
A 48 people, accounting for 4 points, so B 94 people
120 x 2 / 5 equals 48 people 48 divided by 4 times 7 equals 84 people
The number of people in workshop a: 120 * 2 / 5 = 48, after the transfer, the number ratio of the two workshops is 4:7, then the number of people in workshop B: 48 / (4:7) = 84
84
The number a is 2 / 3 of the number B, the number B is 3 / 4 of the number C, the sum of a, B and C is 216, what are the numbers of a, B and C
C: 216 △ (2 / 3 × 3 / 4 + 3 / 4 + 1) = 96
B: 96 × 3 / 4 = 72
A: 72 × 2 / 3 = 48
A = b * 2 / 3, C = b * 4 / 3, the sum of a, B and C is 216, b * 2 / 3 + b * 4 / 3 + B = 216,
3 * b = 216, B = 72, so a = 48, C = 96
Number B: number a = 1.5
Number B: number C = 3:4, number C = 4 / 3, number b = 4 / 3 * 3 / 2, number a = 2
A + B + C = 216
A + 1.5 A + 2 a = 216
4.5 A = 216
A = 48
B = 1.5 A = 1.5 × 48 = 72
C = 2 a = 2 × 48 = 96
Let B be a, then a is 2A / 3, and C is a / (3 / 4) = 4A / 3
a(1+2/3+4/3)=216
3a=216, a=72, 2a/3=48, 4a/3=96
The order of a, B and C is 48, 72 and 96
Let C be x, then B be 3 / 4 * x and a be 2 / 3 * 3 / 4 * X
x+3/4*x+2/3*3/4*x=216
x(1+3/4+1/2)=216
x=216*4/9=96
That is, number C is 96, number B is 3 / 4 * x = 3 / 4 * 96 = 72, number a is 2 / 3 * 3 / 4 * x = 2 / 3 * 3 / 4 * 96 = 48.
A: 512 / 9; B: 256 / 3; C: 1024 / 9
The number of workers in workshop a is 25 of that in workshop B. later, the number of workers in workshop a increased by 20 and that in workshop B decreased by 35. In this way, the number of workers in workshop a is 79 of that in workshop B. now, how many workers are there in workshop a and workshop B?
Suppose the number of people in workshop B is x, then the number of people in workshop a is 79x. According to the meaning of the question, we get: 79x-20 = (x + 35) × 25, 79x-20 = 25X + 35 × 25, 79x-20 = 25X + 14, & nbsp; 1745x = 34, & nbsp; & nbsp; & nbsp; X = 90, the number of people in workshop a: 79x = 90 × 79 = 70
The number a is 2 / 3 of the number B, the number B is 3 / 4 of the number C, and the sum of the three numbers a, B and C is 216. What are the numbers a, B and C?
Urgent need
First find out their ratio, and then distribute them in proportion
Let B be unit 1, then a is 2 / 3 and C is 4 / 3
A: B: C = (2 / 3): 1: (4 / 3) = 2:3:4
2+3+4=9
The number of a is 216 × 2 / 9 = 48
B is 216 × 3 / 9 = 72
The C number is 216 × 4 / 9 = 96
(2/3)*(3/4)=1/2
C 216 / (1 / 2 + 3 / 4 + 1) = 96
A 96 * (1 / 2) = 48
B 96 * (3 / 4) = 72
Let C be x, then B be 3 / 4x and a be 3 / 4x × 2 / 3 = 1 / 2x
1/2x+3/4x+x=216
9/4x=216
x=96
A: 48
B: 72
C: 96
B = 2 / 3
B = 3 / 4 C
A + B + C = 216
2 / 3 B + B + 4 / 3 B = 216
B = 54
A = 36
C = 72
The number of workers in workshop a is 25 of that in workshop B. later, the number of workers in workshop a increased by 20 and that in workshop B decreased by 35. In this way, the number of workers in workshop a is 79 of that in workshop B. now, how many workers are there in workshop a and workshop B?
Suppose the number of people in workshop B is x, then the number of people in workshop a is 79x. According to the meaning of the question, we can get: 79x-20 = (x + 35) × 25, 79x-20 = 25X + 35 × 25, 79x-20 = 25X + 14, & nbsp; 1745x = 34, & nbsp; & nbsp; & nbsp; X = 90, the number of people in workshop a: 79x = 90 × 79 = 70