Divide 16 into the sum of several natural numbers, and then multiply these natural numbers. What is the maximum product

Divide 16 into the sum of several natural numbers, and then multiply these natural numbers. What is the maximum product

16＝3＋3＋3＋3＋2＋2
The maximum is 3 * 3 * 3 * 3 * 2 * 2 = 324
There is a principle of "3 + 3 = 2 + 2 + 2 = 63 * 3 = 92 * 2 * 2 = 8"
So try to remove 3 as much as possible. 2 and 4 are the same, because 2 + 2 = 2 * 2 = 4
There are two workshops a and B in a factory. The number of people in workshop a accounts for 3 / 5 of the two workshops. After 90 people are transferred from workshop a, there are two cars
Let the total number of people be X
（3/5x-90）/（1- 3/5）x+90=2/3
X = 450
A: there were 450 people in the two workshops
Question: there are two workshops in a factory. The number of people in workshop a accounts for 3 / 5 of the two workshops. After 90 people are transferred from workshop a, the ratio of the number of people in workshop a and workshop B is 2:3. How many people are there in the two workshops?
There are three numbers a, B and C. A is two times more than B. B is one third of C. A is three times the sum of B and C. find these three numbers
A is (2Y + 1), B is y, C is 3Y
2y+1=（y+3y)*3
y=1/10
A is 6 / 5, C is 3 / 10
Let B be X
A: 6 / 5
B: 1 / 10
C: 3 / 10
A: 6 / 5
B: 1 / 10
C: 3 / 10
Let a be x, B be y and C be Z
x=2y+1
y=1/3z
x=3(y+z)
Solution
x=1.2 y=0.1 z=0.3
Let C be x, then B = 1 / 3x; a = 2 × B + 1 = 2 / 3x + 1
According to the meaning of the title:
2/3x+1=(1/3x+x)×3
2/3x+1=4x
10/3x=1
x=3/10
3 for C, 0. 1 for B and 1. 2 for a
There are 120 people in factory a and 80 people in factory B. the ratio of the number of people transferred from factory B to factory a is 5:1
Don't write equations, write numbers
(120 + 80) * 5 / (5 + 3) = 125
125-120 = 5
Five people were transferred
There are three numbers a, B and C. the number a is 100 times more than the number B, and the number B is 50 times more than the number C. It is known that the sum of the three numbers is 1650. Find this number
Let C be x, B be 2x + 50, then a be 2 (2x + 50) + 100 = 4x + 200
x+2x+50+4x+200=1650
7x=1400
x=200
2*200+50=450
4*200+200=1000
therefore
1000 for a, 450 for B and 200 for C
Arithmetic method, C = (1650-200-50) / (2 × 2 + 2 + 1) = 200
B = 200 × 2 + 50 = 450
A = 200 × 4 + 200 = 100
Let C be x, then B be 2x + 50, a be 2 (2x + 50) + 100 = 4x + 200, then a + B + C = 7x + 250 = 165,
have to
X = - 85 / 7, then a = 1060 / 7, B = 180 / 7, C = - 85 / 7
This kind of problem is like primary school or junior one. It mainly tests the students' mastery of setting unknown sequence equation. To do this kind of problem is to replace the smallest number or the easiest number with X, and then other numbers are represented by 2x, 0.5x + 1 and so on. According to the conditions, it is OK to list the equation and solve it. ... unfold
Let C be x, then B be 2x + 50, a be 2 (2x + 50) + 100 = 4x + 200, then a + B + C = 7x + 250 = 165,
have to
X = - 85 / 7, then a = 1060 / 7, B = 180 / 7, C = - 85 / 7
This kind of problem is like primary school or junior one. It mainly tests the students' mastery of setting unknown sequence equation. To do this kind of problem is to replace the smallest number or the easiest number with X, and then other numbers are represented by 2x, 0.5x + 1 and so on. According to the conditions, it is OK to list the equation and solve it. Put it away
The average number of people in the two workshops is 120, and the ratio of the two workshops is 8:7?
A + 2 × 8 / (120)
=240×8/15
=128
B 120 × 2-128 = 112 persons
There are three numbers of a, B and C. B is 13 more than C. A is two times of B. the sum of the three numbers is a prime number less than 50, and the sum of the three numbers is 11. Try to find the three numbers of a, B and C
Let C be X
Then B: (x + 13), a, 2 (x + 13)
The sum of three is 4x + 39
If the sum is less than 50, then
4x+39
There are 120 workers in the two workshops. After transferring 20% of the number of workers in workshop a to workshop B, the ratio of the number of workers in workshop a and workshop B is 2:3. How many workers are there in workshop a
Formula and result
Now, a is half of the total
2 ÷ (2 + 3) = 2 / 5
It turns out that a is half of the total number
2 / 5 (1-20%) = 1 / 2
There were workers in workshop a
120 × 1 / 2 = 60 persons
The number a is 5 / 6 of the number B, the number B is 3 / 4 of the number C, the sum of the numbers a, B and C is 152, and what are the numbers a, B and C
Number B: 152 ÷ (5 / 6 + 1 + 4 / 3) = 48
Number of a: 48 × 5 / 6 = 40
C number: 48 △ 3 / 4 = 64
There are 120 employees in workshop a and workshop B. after 10 employees are transferred from workshop B to workshop a, the ratio of workshop a and workshop B is 5:3. How many employees are there in workshop a?
fast
There are x people in workshop a and 120-x people in workshop B
According to the meaning of the title
(x+10)/(120-x-10)=5/3
x=65
Workshop B 120-x = 55