How many different shapes does a rectangle have when its length and width are natural numbers and its area is 165? (just describe the shape in words!)

How many different shapes does a rectangle have when its length and width are natural numbers and its area is 165? (just describe the shape in words!)

165 = 1 * 3 * 5 * 11, 4 kinds in length and width
165 1
55 3
33 5
15 11
How many different shapes of rectangles with natural number long sides and 165 area are there?
The factors of 165 are: 1,3,5,11,33,55165
1*165=165,
3*55=165
5*33=165
11*15=165
The side length is a natural number, and the area is 165 square centimeters. There are four different shapes of rectangles
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The ratio of people in workshop a and workshop B is 3:5. If 10 people are transferred from workshop B to workshop a, now the ratio of people in workshop a and workshop B is 2:3. How many people are there in workshop a?
If there are 3x people in the original workshop a, then the workshop B is a 5x person. According to the meaning of the topic, we can get: (3x + 10): (3x + 10): (5x-10-10) (5x-10) = 2:3, 3:3, 3:3, 3:3, according to the meaning of the topic: (3x + 10): (3x + 10): (3x + 10): (5x-10-10) (5x-10-10) = 2:3, 3, 3, 3, and & nbsp; according to the meaning of the topic can be: (3x + 10): (3x + 10): (3x + 10): (3x + 10): (3x + 10): (3x + 10): (3x + 10): (3x + 10): (3x + 10): (3x + 10): (3x + 10): (3x + 10): (3x + 10): (3x + 10): (3x + 10): (3x + 10): (3x + 10): (3xsp; &X = 10, 10 × 3 = 30 (people), a: there were 30 people in workshop a
There are three numbers: A, B and C. The average number of a and B is 21.5, the average number of B and C is 22.5, and the average number of a and C is 16?
The sum of a, B and C is (21.5 * 2 + 22.5 * 2 + 16 * 2) △ 2 = 60
C = 60-21.5 * 2 = 17
A = 60-22.5 * 2 = 15
B = 60-16 * 2 = 28
The number of people in workshop a is 30 less than that in workshop B, and the number of people in workshop a is 5 more than 1 / 10 of that in workshop B. how many people are there in the two workshops
If there are x persons in B, there are:
x-30=x/10+5;
9x/10=35;
x=350/9;
It's not an integer; there's something wrong with the numbers
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The average number of the three numbers is 120. The number of a is twice that of B. the number of C is 5 more than that of A. what are the numbers of a, B and C?
Let B be x, then a is 2x and C is 2x + 5. According to the meaning of the question, we can get the equation: x + 2x + 2x + 5 = 120 × 3 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 5x + 5 = 360 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 5x = 355 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 71, so a is 71 × 2 = 142 and C is 142 + 5 = 147 a: A is 142, B is 71 and C is 147
There are 180 workers in workshop a and 120 workers in workshop B of a factory. Now 50 workers are transferred from the two workshops to support the new factory. Due to the increase of workload, the rest of the workers increase their wages by 20% every day. Due to different types of work, the wages of workers in workshop a and workshop B are 60 yuan and 48 yuan respectively. It is known that the total wages of the factory are the same as before. There are many workers in workshop a_ _____ People
60 (1 + 20%), = 60 (120%), = 50 (yuan). 180 × 50 (60), = 9000 (60), = 150 (people); answer: there are 150 workers in workshop a
The average number of a and B is 25, the average number of a, B and C is 24, and the average number of C is 25______ .
24 × 3-25 × 2, = 72-50, = 22.; answer: C number is 22
There are 94 workers in the two workshops. Due to the need of work, 46 workers are transferred from B to A. at this time, B has 12 fewer workers than A. how many workers are there in a and B?
 
There are three numbers of a, B and C, and the average number of a and B is 30
The average number of a and B is 30, the average number of B and C is 34, the average number of a and C is 32, what are the three numbers of a, B and C?
Thank you`
How to solve arithmetic
30 + 34 + 32 = 96 C: 96-30 * 2 = 36 A: 96-34 * 2 = 28 B: 96-32 * 2 = 32 consider: add three average values to get the sum of three numbers (if you can't understand it, you can think like this: add a and B equals 30 * 2... And so on, the result is the result of adding two a, two B and two C, which is the same as before)
Let a be a, B be B and C be c
(a+b)/2=30 =>a+b=60-------1
(b+c)/2=34 =>b+c=68-------2
(a+c)/2=32 =>a+c=64-------3
1-2+3=>a=28
Take it back B = 32 c = 36
Arithmetic solution:
The sum of a and B is 60, B and C is 68, a and C is 64
So the sum of a and B + B and C + A and C
Let a be a, B be B and C be c
(a+b)/2=30 =>a+b=60-------1
(b+c)/2=34 =>b+c=68-------2
(a+c)/2=32 =>a+c=64-------3
1-2+3=>a=28
Take it back B = 32 c = 36
Arithmetic solution:
The sum of a and B is 60, B and C is 68, a and C is 64
Then the sum of a and B + B and C + A and C is 60 + 68 + 64 = 132
Actually, the sum of a + B + C is 66
Compared with the previous, the sum of a and B is 60, then C is 36
Then even if B is 32, a is 28, put it away
Let a, B and C be x, y and Z respectively
X+Y=60
Y+Z=68
X+Z=64
The solution is x = 28, y = 32, z = 36