There are two warehouses of a and B. the grain stored in warehouse A is 80 tons. If 16 / 3 of the grain is transported from warehouse A and put into warehouse B, the stock of the two warehouses is equal. How many tons of grain was originally stored in warehouse B 16 / 3 to 3 / 16

There are two warehouses of a and B. the grain stored in warehouse A is 80 tons. If 16 / 3 of the grain is transported from warehouse A and put into warehouse B, the stock of the two warehouses is equal. How many tons of grain was originally stored in warehouse B 16 / 3 to 3 / 16

If 3 / 16 of 80 tons is 15 tons, then 80-15 = 65 tons for Party A and Party B respectively,
Minus 15 tons put in, B warehouse was 65 - 15 = 50 tons
The number a is only two-thirds of the number B, the number B is one-fifth of the number C, and the sum of a, B and C is 300
Let C be X,
B: 1 / 5x
A: (2 / 3) * (1 / 5) x = 2 / 15x
2/15x+1/5x+x=300
∴x=225
A = 30, B = 45, C = 225
The original number of people in workshop a and workshop B is 3:2, and 30 people are transferred from workshop a to workshop B. how many people are there in workshop a and workshop B?
There were 3x people in workshop a and 2x people in workshop B
3x-30=2x+30
x=60
3x=180
2x=120
The average number of the three numbers is 120. The number of a is twice that of B. the number of C is 5 more than that of A. what are the three numbers of a, B and C?
Urgent! 11111
B is one, a has three, C is five more than three
So B is (120-5) / (1 + 3 + 3) = 15
A is 15 * 3 = 45
C is 45 + 5 = 50
B is one, a has three, C is five more than three
So B is (120-5) / (1 + 3 + 3) = 15
A is 15 * 3 = 45
C is 45 + 5 = 50
A is 142, B is 71, C is 147
Let B be x, then a be 2x and C be 2x + 5
x+2x+2x+5=120*3
=>x=71
So a is 2 * 71 = 142, B is 71, C is 142 + 5 = 147
Hello
One hundred and forty-two
Seventy-one
One hundred and forty-seven
It should be, right
120X3=360
360-5=355
355 / 5 = 71 B
71x2 = 142 a
142 + 5 = 147 C
Sum of three numbers: 120x3 = 360
B: (360-5) / (1 + 2 + 2) = 71
A: 71x2 = 142
C: 142 + 5 = 147
There are 94 workers in a workshop, one fourth of them are male workers, one less than one third of them are female workers. How many are male and female workers in this workshop?
Set the number of male workers as X and the number of female workers as y
x＋y＝94
1/3 y－1/4 x＝1
The solution is: x = 52
y＝42
Suppose male x female 94-x
1/4x+1=1/3(94-x)
1/4x+1/3x=94/3-1
7/12x=91/3
x=52
Male 52, female = 94-52 = 42
Set male X
x/4+1=(94-x)/3
x=52
Male 52, female = 94-52 = 42
If there are x male workers, 94-x female workers can get:
(94-x)/3-x/4=1
376-4x-3x=12
7x=364
x=52
Female workers: 94-x = 94-52 = 42
There must be a mistake in the title. The number of male workers calculated in this way is not a whole number!! How can a living man split half of it?
There are x male workers and 94-x female workers.
（1/4）X=（1/3）（94-X）-1
3X=4（94-X）-12
3X=376-4X-12
7X=364
X=52
There are 52 male workers and 42 female workers
If the number of male workers is x, the number of female workers is 94-x.
1/4*X=(94—X)/3—1
X=52
That is to say, the number of male workers is 52, while the number of female workers is 42
94-x female workers
1/4*x=1/3*(94-x)-1
7x=364
x=52
There are 52 male workers and 42 female workers
Tao
If there are x male workers, 94-x female workers can get:
(94-x)/3-x/4=1
376-4x-3x=12
7x=364
x=52
Female workers: 94-x = 94-52 = 42
The sum of a, B and C is 300, a is 120, C is 45 of B, C is ()
A. 80B. 100C. 180
Number B: (300-120) △ 1 + 45, = 180 △ 95, = 100; number C: 180-100 = 80
The number of male workers is three more than that of female workers. If there are two more male workers and four fewer female workers, the number of male and female workers is equal
How many men and women were there in this workshop
Setting: X male workers and Y female workers,
According to the meaning of the title:
3/2x-3=y
x+2=y-4
The solution of the equation
x=18
y=24
A: there are 18 men and 24 women in the workshop
The number of B and C is 120, and the number of B and C is 4:30
If 5 times the number of a is exactly 8 times the number of B, then the ratio of a to B is ()
The sum of the three numbers of a, B and C is 120, the number of a is 30, the ratio of B to C is 4:5, the number of B is (40), and the number of C is (50)
If the number of a is 5 times that of B, then the ratio of a to B is (8:5)
(1) B is 40, C is 50
（2）8:5
There are 52 workers in a workshop, one fourth of them are male workers, one less than one third of them are female workers. How many are male workers and female workers
There are x boys and 52-x girls
1/3（52-x）-1/4x=1
52/3-1/3x-1/4x=1
52/3-7/12x=1
7/12x=49/3
x=28
Female: 52-28 = 24
28 24
The sum of a, B and C is 120, B is 9 / 5 times of a, C is 4 times of the difference between a and B
Let a be x, B be 9 / 5 x, C be 4 (9 / 5-x)
x+9/5 X+4(9/5-x) =120
x+9/5 X+36/5X-4x=120
10X-4X=120
X=20
So the number a is 20, the number B is 36, and the number C is 64
Let a, B and C be a, B and C respectively
According to the meaning of the title:
a+b+c=120………… (1)
b=(9/5)*a………… II.
∵b>a
∴c=4*(b-a)……… 3.
Bring (2) into (1)
a+(9/5)*a+(16/5)*a=120
Solution
a=20
b=36
c=64
There are two groups
1、 20, 36, 64
2、 - 300, - 540960
Is this hard? Did you copy the wrong title? If C is four times the difference between a and B, then a + (a * 9 / 5) + 4 * (a - (a * 9 / 5)) = 120
Self interpretation
If C is four times the difference between B and a, then a + (a * 9 / 5) + 4 * ((a * 9 / 5) - a) = 120
A = 20, B = 36, C = 64
Let a be a, then B be a * 9 / 5 and C be (a * 9 / 5-a) * 4.
a+a*9/5+（a*9/5-a）*4=120
Then a = 20
A, B and C were 20, 36 and 64 respectively.