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證明:∵四邊形ABCD是平行四邊形,∴AB=CD,AB‖CD,∴∠A+∠D=180°,在△ABM和△DCM中,AM=DMAB=DCBM=CM,∴△ABM≌△DCM,∴∠A=∠D=90°,即可得出平行四邊形ABCD是矩形.
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